Запрос - SELECT DISTINCT `b`.`id`, `b`.`url`, `b`.`image`, `b`.`last_modify`, `b`.`visible`, `b`.`position`, `l`.`name`, `l`.`meta_title`, `l`.`meta_keywords`, `l`.`meta_description`, `l`.`annotation`, `l`.`description` FROM `ok_brands` AS `b` LEFT JOIN `ok_products` AS `p` ON `p`.`brand_id`=`b`.`id...